Extracting extension from filename in Python Extracting extension from filename in Python python python

Extracting extension from filename in Python


Yes. Use os.path.splitext(see Python 2.X documentation or Python 3.X documentation):

>>> import os>>> filename, file_extension = os.path.splitext('/path/to/somefile.ext')>>> filename'/path/to/somefile'>>> file_extension'.ext'

Unlike most manual string-splitting attempts, os.path.splitext will correctly treat /a/b.c/d as having no extension instead of having extension .c/d, and it will treat .bashrc as having no extension instead of having extension .bashrc:

>>> os.path.splitext('/a/b.c/d')('/a/b.c/d', '')>>> os.path.splitext('.bashrc')('.bashrc', '')


import os.pathextension = os.path.splitext(filename)[1]


New in version 3.4.

import pathlibprint(pathlib.Path('yourPath.example').suffix) # '.example'

I'm surprised no one has mentioned pathlib yet, pathlib IS awesome!

If you need all the suffixes (eg if you have a .tar.gz), .suffixes will return a list of them!


matomo