Filter out elements that occur less times than a minimum threshold
Build your Counter, then use a dict comprehension as a second, filtering step.
{x: count for x, count in A.items() if count >= min_threshold}# {'a': 4, 'b': 3}
You could remove the keys from the dictionary that are below 3:
for key, cnts in list(A.items()): # list is important here if cnts < min_threshold: del A[key]Which gives you:
>>> ACounter({'a': 4, 'b': 3})
As covered by Satish BV, you can iterate over your Counter with a dictionary comprehension. You could use items (or iteritems for more efficiency and if you're on Python 2) to get a sequence of (key, value) tuple pairs.And then turn that into a Counter.
my_dict = {k: v for k, v in A.iteritems() if v >= min_threshold}filteredA = Counter(my_dict)Alternatively, you could iterate over the original Counter and remove the unnecessary values.
for k, v in A.items(): if v < min_threshold: A.pop(k)