'function' object has no attribute 'as_view'
IngredientCreateView should be a class.So your views.py replace:
def IngredientCreateView(CreateView):with:
class IngredientCreateView(CreateView):
In my case, the problem was that I tried to use a @decorator on the class-based view as if it was a function-based view, instead of @decorating the class correctly.
EDIT: From the linked page, here is a way to apply @login_required to a class-based view:
from django.contrib.auth.decorators import login_requiredfrom django.utils.decorators import method_decorator@method_decorator(login_required, name='dispatch')class ProtectedView(TemplateView):
IngredientCreateView is a function, not a class.
The following line
def IngredientCreateView(CreateView):should be replace with
class IngredientCreateView(CreateView):