Generate 'n' unique random numbers within a range [duplicate]

If you just need sampling without replacement:

>>> import random>>> random.sample(range(1, 100), 3)[77, 52, 45]

random.sample takes a population and a sample size k and returns k random members of the population.

If you have to control for the case where k is larger than len(population), you need to be prepared to catch a ValueError:

>>> try:...   random.sample(range(1, 2), 3)... except ValueError:...   print('Sample size exceeded population size.')... Sample size exceeded population size

Generate the range of data first and then shuffle it like this

import randomdata = range(numLow, numHigh)random.shuffle(data)print data

By doing this way, you will get all the numbers in the particular range but in a random order.

But you can use random.sample to get the number of elements you need, from a range of numbers like this

print random.sample(range(numLow, numHigh), 3)

You could add to a set until you reach n:

setOfNumbers = set()while len(setOfNumbers) < n:    setOfNumbers.add(random.randint(numLow, numHigh))

Be careful of having a smaller range than will fit in n. It will loop forever, unable to find new numbers to insert up to n