The pythonic way is to use enumerate:
for idx,item in enumerate(list):
Agree with Nick. Here is more elaborated code.
#count=0for idx, item in enumerate(list): print item #count +=1 #if count % 10 == 0: if (idx+1) % 10 == 0: print 'did ten'
I have commented out the count variable in your code.
I know rather old question but....came across looking other thing so I give my shot:
[each*2 for each in [1,2,3,4,5] if each % 10 == 0])