Get statistics for each group (such as count, mean, etc) using pandas GroupBy? Get statistics for each group (such as count, mean, etc) using pandas GroupBy? python python

# Get statistics for each group (such as count, mean, etc) using pandas GroupBy?

The simplest way to get row counts per group is by calling `.size()`, which returns a `Series`:

``df.groupby(['col1','col2']).size()``

Usually you want this result as a `DataFrame` (instead of a `Series`) so you can do:

``df.groupby(['col1', 'col2']).size().reset_index(name='counts')``

If you want to find out how to calculate the row counts and other statistics for each group continue reading below.

## Detailed example:

Consider the following example dataframe:

``In [2]: dfOut[2]:   col1 col2  col3  col4  col5  col60    A    B  0.20 -0.61 -0.49  1.491    A    B -1.53 -1.01 -0.39  1.822    A    B -0.44  0.27  0.72  0.113    A    B  0.28 -1.32  0.38  0.184    C    D  0.12  0.59  0.81  0.665    C    D -0.13 -1.65 -1.64  0.506    C    D -1.42 -0.11 -0.18 -0.447    E    F -0.00  1.42 -0.26  1.178    E    F  0.91 -0.47  1.35 -0.349    G    H  1.48 -0.63 -1.14  0.17``

First let's use `.size()` to get the row counts:

``In [3]: df.groupby(['col1', 'col2']).size()Out[3]: col1  col2A     B       4C     D       3E     F       2G     H       1dtype: int64``

Then let's use `.size().reset_index(name='counts')` to get the row counts:

``In [4]: df.groupby(['col1', 'col2']).size().reset_index(name='counts')Out[4]:   col1 col2  counts0    A    B       41    C    D       32    E    F       23    G    H       1``

### Including results for more statistics

When you want to calculate statistics on grouped data, it usually looks like this:

``In [5]: (df   ...: .groupby(['col1', 'col2'])   ...: .agg({   ...:     'col3': ['mean', 'count'],    ...:     'col4': ['median', 'min', 'count']   ...: }))Out[5]:             col4                  col3                median   min count      mean countcol1 col2                                   A    B    -0.810 -1.32     4 -0.372500     4C    D    -0.110 -1.65     3 -0.476667     3E    F     0.475 -0.47     2  0.455000     2G    H    -0.630 -0.63     1  1.480000     1``

The result above is a little annoying to deal with because of the nested column labels, and also because row counts are on a per column basis.

To gain more control over the output I usually split the statistics into individual aggregations that I then combine using `join`. It looks like this:

``In [6]: gb = df.groupby(['col1', 'col2'])   ...: counts = gb.size().to_frame(name='counts')   ...: (counts   ...:  .join(gb.agg({'col3': 'mean'}).rename(columns={'col3': 'col3_mean'}))   ...:  .join(gb.agg({'col4': 'median'}).rename(columns={'col4': 'col4_median'}))   ...:  .join(gb.agg({'col4': 'min'}).rename(columns={'col4': 'col4_min'}))   ...:  .reset_index()   ...: )   ...: Out[6]:   col1 col2  counts  col3_mean  col4_median  col4_min0    A    B       4  -0.372500       -0.810     -1.321    C    D       3  -0.476667       -0.110     -1.652    E    F       2   0.455000        0.475     -0.473    G    H       1   1.480000       -0.630     -0.63``

### Footnotes

The code used to generate the test data is shown below:

``In [1]: import numpy as np   ...: import pandas as pd    ...:    ...: keys = np.array([   ...:         ['A', 'B'],   ...:         ['A', 'B'],   ...:         ['A', 'B'],   ...:         ['A', 'B'],   ...:         ['C', 'D'],   ...:         ['C', 'D'],   ...:         ['C', 'D'],   ...:         ['E', 'F'],   ...:         ['E', 'F'],   ...:         ['G', 'H']    ...:         ])   ...:    ...: df = pd.DataFrame(   ...:     np.hstack([keys,np.random.randn(10,4).round(2)]),    ...:     columns = ['col1', 'col2', 'col3', 'col4', 'col5', 'col6']   ...: )   ...:    ...: df[['col3', 'col4', 'col5', 'col6']] = \   ...:     df[['col3', 'col4', 'col5', 'col6']].astype(float)   ...: ``

Disclaimer:

If some of the columns that you are aggregating have null values, then you really want to be looking at the group row counts as an independent aggregation for each column. Otherwise you may be misled as to how many records are actually being used to calculate things like the mean because pandas will drop `NaN` entries in the mean calculation without telling you about it.

On `groupby` object, the `agg` function can take a list to apply several aggregation methods at once. This should give you the result you need:

``df[['col1', 'col2', 'col3', 'col4']].groupby(['col1', 'col2']).agg(['mean', 'count'])``

## Swiss Army Knife: `GroupBy.describe`

Returns `count`, `mean`, `std`, and other useful statistics per-group.

``df.groupby(['A', 'B'])['C'].describe()           count  mean   std   min   25%   50%   75%   maxA   B                                                     bar one      1.0  0.40   NaN  0.40  0.40  0.40  0.40  0.40    three    1.0  2.24   NaN  2.24  2.24  2.24  2.24  2.24    two      1.0 -0.98   NaN -0.98 -0.98 -0.98 -0.98 -0.98foo one      2.0  1.36  0.58  0.95  1.15  1.36  1.56  1.76    three    1.0 -0.15   NaN -0.15 -0.15 -0.15 -0.15 -0.15    two      2.0  1.42  0.63  0.98  1.20  1.42  1.65  1.87``

To get specific statistics, just select them,

``df.groupby(['A', 'B'])['C'].describe()[['count', 'mean']]           count      meanA   B                     bar one      1.0  0.400157    three    1.0  2.240893    two      1.0 -0.977278foo one      2.0  1.357070    three    1.0 -0.151357    two      2.0  1.423148``

`describe` works for multiple columns (change `['C']` to `['C', 'D']`â€”or remove it altogetherâ€”and see what happens, the result is a MultiIndexed columned dataframe).

You also get different statistics for string data. Here's an example,

``df2 = df.assign(D=list('aaabbccc')).sample(n=100, replace=True)with pd.option_context('precision', 2):    display(df2.groupby(['A', 'B'])               .describe(include='all')               .dropna(how='all', axis=1))              C                                                   D                          count  mean       std   min   25%   50%   75%   max count unique top freqA   B                                                                              bar one    14.0  0.40  5.76e-17  0.40  0.40  0.40  0.40  0.40    14      1   a   14    three  14.0  2.24  4.61e-16  2.24  2.24  2.24  2.24  2.24    14      1   b   14    two     9.0 -0.98  0.00e+00 -0.98 -0.98 -0.98 -0.98 -0.98     9      1   c    9foo one    22.0  1.43  4.10e-01  0.95  0.95  1.76  1.76  1.76    22      2   a   13    three  15.0 -0.15  0.00e+00 -0.15 -0.15 -0.15 -0.15 -0.15    15      1   c   15    two    26.0  1.49  4.48e-01  0.98  0.98  1.87  1.87  1.87    26      2   b   15``

## pandas >= 1.1: `DataFrame.value_counts`

This is available from pandas 1.1 if you just want to capture the size of every group, this cuts out the `GroupBy` and is faster.

``df.value_counts(subset=['col1', 'col2'])``

Minimal Example

``# Setupnp.random.seed(0)df = pd.DataFrame({'A' : ['foo', 'bar', 'foo', 'bar',                          'foo', 'bar', 'foo', 'foo'],                   'B' : ['one', 'one', 'two', 'three',                          'two', 'two', 'one', 'three'],                   'C' : np.random.randn(8),                   'D' : np.random.randn(8)})df.value_counts(['A', 'B']) A    B    foo  two      2     one      2     three    1bar  two      1     three    1     one      1dtype: int64``

## Other Statistical Analysis Tools

If you didn't find what you were looking for above, the User Guide has a comprehensive listing of supported statical analysis, correlation, and regression tools.