Getting a list of all subdirectories in the current directory Getting a list of all subdirectories in the current directory python python

Getting a list of all subdirectories in the current directory


Do you mean immediate subdirectories, or every directory right down the tree?

Either way, you could use os.walk to do this:

os.walk(directory)

will yield a tuple for each subdirectory. Ths first entry in the 3-tuple is a directory name, so

[x[0] for x in os.walk(directory)]

should give you all of the subdirectories, recursively.

Note that the second entry in the tuple is the list of child directories of the entry in the first position, so you could use this instead, but it's not likely to save you much.

However, you could use it just to give you the immediate child directories:

next(os.walk('.'))[1]

Or see the other solutions already posted, using os.listdir and os.path.isdir, including those at "How to get all of the immediate subdirectories in Python".


You could just use glob.glob

from glob import globglob("/path/to/directory/*/")

Don't forget the trailing / after the *.


import osd = '.'[os.path.join(d, o) for o in os.listdir(d)                     if os.path.isdir(os.path.join(d,o))]


matomo