How can I check the extension of a file?
Assuming m is a string, you can use endswith:
if m.endswith('.mp3'):...elif m.endswith('.flac'):...To be case-insensitive, and to eliminate a potentially large else-if chain:
m.lower().endswith(('.png', '.jpg', '.jpeg'))
os.path provides many functions for manipulating paths/filenames. (docs)
os.path.splitext takes a path and splits the file extension from the end of it.
import osfilepaths = ["/folder/soundfile.mp3", "folder1/folder/soundfile.flac"]for fp in filepaths: # Split the extension from the path and normalise it to lowercase. ext = os.path.splitext(fp)[-1].lower() # Now we can simply use == to check for equality, no need for wildcards. if ext == ".mp3": print fp, "is an mp3!" elif ext == ".flac": print fp, "is a flac file!" else: print fp, "is an unknown file format."Gives:
/folder/soundfile.mp3 is an mp3!folder1/folder/soundfile.flac is a flac file!
Use pathlib From Python3.4 onwards.
from pathlib import PathPath('my_file.mp3').suffix == '.mp3'