How can I get all the request headers in Django?

According to the documentation request.META is a "standard Python dictionary containing all available HTTP headers". If you want to get all the headers you can simply iterate through the dictionary.

Which part of your code to do this depends on your exact requirement. Anyplace that has access to request should do.

Update

I need to access it in a Middleware class but when i iterate over it, I get a lot of values apart from HTTP headers.

From the documentation:

With the exception of CONTENT_LENGTH and CONTENT_TYPE, as given above, any HTTP headers in the request are converted to META keys by converting all characters to uppercase, replacing any hyphens with underscores and adding an HTTP_ prefix to the name.

(Emphasis added)

To get the HTTP headers alone, just filter by keys prefixed with HTTP_.

Update 2

could you show me how I could build a dictionary of headers by filtering out all the keys from the request.META variable which begin with a HTTP_ and strip out the leading HTTP_ part.

Sure. Here is one way to do it.

import reregex = re.compile('^HTTP_')dict((regex.sub('', header), value) for (header, value)        in request.META.items() if header.startswith('HTTP_'))

Starting from Django 2.2, you can use request.headers to access the HTTP headers. From the documentation on HttpRequest.headers:

A case insensitive, dict-like object that provides access to all HTTP-prefixed headers (plus Content-Length and Content-Type) from the request.

The name of each header is stylized with title-casing (e.g. User-Agent) when it’s displayed. You can access headers case-insensitively:

>>> request.headers{'User-Agent': 'Mozilla/5.0 (Macintosh; Intel Mac OS X 10_12_6', ...}>>> 'User-Agent' in request.headersTrue>>> 'user-agent' in request.headersTrue>>> request.headers['User-Agent']Mozilla/5.0 (Macintosh; Intel Mac OS X 10_12_6)>>> request.headers['user-agent']Mozilla/5.0 (Macintosh; Intel Mac OS X 10_12_6)>>> request.headers.get('User-Agent')Mozilla/5.0 (Macintosh; Intel Mac OS X 10_12_6)>>> request.headers.get('user-agent')Mozilla/5.0 (Macintosh; Intel Mac OS X 10_12_6)

To get all headers, you can use request.headers.keys() or request.headers.items().

This is another way to do it, very similar to Manoj Govindan's answer above:

import reregex_http_          = re.compile(r'^HTTP_.+$')regex_content_type   = re.compile(r'^CONTENT_TYPE$')regex_content_length = re.compile(r'^CONTENT_LENGTH$')request_headers = {}for header in request.META:    if regex_http_.match(header) or regex_content_type.match(header) or regex_content_length.match(header):        request_headers[header] = request.META[header]

That will also grab the CONTENT_TYPE and CONTENT_LENGTH request headers, along with the HTTP_ ones. request_headers['some_key] == request.META['some_key'].

Modify accordingly if you need to include/omit certain headers. Django lists a bunch, but not all, of them here: https://docs.djangoproject.com/en/dev/ref/request-response/#django.http.HttpRequest.META

Django's algorithm for request headers:

1. Replace hyphen - with underscore _
2. Convert to UPPERCASE.
3. Prepend HTTP_ to all headers in original request, except for CONTENT_TYPE and CONTENT_LENGTH.

The values of each header should be unmodified.