How can I remove text within parentheses with a regex?

s/\([^)]*\)//

So in Python, you'd do:

re.sub(r'\([^)]*\)', '', filename)

The pattern that matches substrings in parentheses having no other ( and ) characters in between (like (xyz 123) in Text (abc(xyz 123)) is

\([^()]*\)

Details:

• \( - an opening round bracket (note that in POSIX BRE, ( should be used, see sed example below)
• [^()]* - zero or more (due to the * Kleene star quantifier) characters other than those defined in the negated character class/POSIX bracket expression, that is, any chars other than ( and )
• \) - a closing round bracket (no escaping in POSIX BRE allowed)

Removing code snippets:

• JavaScript: string.replace(/\([^()]*\)/g, '')
• PHP: preg_replace('~\([^()]*\)~', '', $string)
• Perl: $s =~ s/\([^()]*\)//g
• Python: re.sub(r'\([^()]*\)', '', s)
• C#: Regex.Replace(str, @"\([^()]*\)", string.Empty)
• VB.NET: Regex.Replace(str, "\([^()]*\)", "")
• Java: s.replaceAll("\\([^()]*\\)", "")
• Ruby: s.gsub(/\([^()]*\)/, '')
• R: gsub("\\([^()]*\\)", "", x)
• Lua: string.gsub(s, "%([^()]*%)", "")
• Bash/sed: sed 's/([^()]*)//g'
• Tcl: regsub -all {\([^()]*\)} $s "" result
• C++ std::regex: std::regex_replace(s, std::regex(R"(\([^()]*\))"), "")
• Objective-C:
  NSRegularExpression *regex = [NSRegularExpression regularExpressionWithPattern:@"\\([^()]*\\)" options:NSRegularExpressionCaseInsensitive error:&error];NSString *modifiedString = [regex stringByReplacingMatchesInString:string options:0 range:NSMakeRange(0, [string length]) withTemplate:@""];
• Swift: s.replacingOccurrences(of: "\\([^()]*\\)", with: "", options: [.regularExpression])

I would use:

\([^)]*\)