How can I return a default value for an attribute? [duplicate]

You should use the getattr wrapper instead of directly retrieving the value of id.

a = getattr(myobject, 'id', None)

This is like saying "I would like to retrieve the attribute id from the object myobject, but if there is no attribute id inside the object myobject, then return None instead." But it does it efficiently.

Some objects also support the following form of getattr access:

a = myobject.getattr('id', None)

As per OP request, 'deep getattr':

def deepgetattr(obj, attr):    """Recurses through an attribute chain to get the ultimate value."""    return reduce(getattr, attr.split('.'), obj)# usage: print deepgetattr(universe, 'galaxy.solarsystem.planet.name')

Simple explanation:

Reduce is like an in-place recursive function. What it does in this case is start with the obj (universe) and then recursively get deeper for each attribute you try to access using getattr, so in your question it would be like this:

a = getattr(getattr(myobject, 'id', None), 'number', None)

The simplest way is to use the ternary operator:

a = myobject.id if myobject is not None else None

The ternary operator returns the first expression if the middle value is true, otherwise it returns the latter expression.

Note that you could also do this in another way, using exceptions:

try:    a = myobject.idexcept AttributeError:    a = None

This fits the Pythonic ideal that it's easier to ask for forgiveness than permission - what is best will depend on the situation.

in my object class you can put override

class Foo(object):   def __getattribute__(self, name):      if not name in self;        return None;      else:        # Default behaviour        return object.__getattribute__(self, name)