How do I check whether a file exists without exceptions?
If the reason you're checking is so you can do something like
if file_exists: open_it(), it's safer to use a
try around the attempt to open it. Checking and then opening risks the file being deleted or moved or something between when you check and when you try to open it.
If you're not planning to open the file immediately, you can use
Trueif path is an existing regular file. This follows symbolic links, so both islink() and isfile() can be true for the same path.
if you need to be sure it's a file.
Starting with Python 3.4, the
pathlib module offers an object-oriented approach (backported to
pathlib2 in Python 2.7):
from pathlib import Pathmy_file = Path("/path/to/file")if my_file.is_file(): # file exists
To check a directory, do:
if my_file.is_dir(): # directory exists
To check whether a
Path object exists independently of whether is it a file or directory, use
if my_file.exists(): # path exists
You can also use
resolve(strict=True) in a
try: my_abs_path = my_file.resolve(strict=True)except FileNotFoundError: # doesn't existelse: # exists
You have the
True for both files and directories but you can instead use
to test if it's a file specifically. It follows symlinks.
exists() will return
True for directories. So depending on if you want only plain files or also directories, you'll use
exists(). Here is some simple REPL output: