How do I create a slug in Django?

You will need to use the slugify function.

>>> from django.template.defaultfilters import slugify>>> slugify("b b b b")u'b-b-b-b'>>>

You can call slugify automatically by overriding the save method:

class Test(models.Model):    q = models.CharField(max_length=30)    s = models.SlugField()        def save(self, *args, **kwargs):        self.s = slugify(self.q)        super(Test, self).save(*args, **kwargs)

Be aware that the above will cause your URL to change when the q field is edited, which can cause broken links. It may be preferable to generate the slug only once when you create a new object:

class Test(models.Model):    q = models.CharField(max_length=30)    s = models.SlugField()        def save(self, *args, **kwargs):        if not self.id:            # Newly created object, so set slug            self.s = slugify(self.q)        super(Test, self).save(*args, **kwargs)

There is corner case with some utf-8 characters

Example:

>>> from django.template.defaultfilters import slugify>>> slugify(u"test ąęśćółń")u'test-aescon' # there is no "l"

This can be solved with Unidecode

>>> from unidecode import unidecode>>> from django.template.defaultfilters import slugify>>> slugify(unidecode(u"test ąęśćółń"))u'test-aescoln'

A small correction to Thepeer's answer: To override save() function in model classes, better add arguments to it:

from django.utils.text import slugifydef save(self, *args, **kwargs):    if not self.id:        self.s = slugify(self.q)    super(test, self).save(*args, **kwargs)

Otherwise, test.objects.create(q="blah blah blah") will result in a force_insert error (unexpected argument).