How do I list all files of a directory? How do I list all files of a directory? python python

How do I list all files of a directory?


os.listdir() will get you everything that's in a directory - files and directories.

If you want just files, you could either filter this down using os.path:

from os import listdirfrom os.path import isfile, joinonlyfiles = [f for f in listdir(mypath) if isfile(join(mypath, f))]

or you could use os.walk() which will yield two lists for each directory it visits - splitting into files and dirs for you. If you only want the top directory you can break the first time it yields

from os import walkf = []for (dirpath, dirnames, filenames) in walk(mypath):    f.extend(filenames)    break

or, shorter:

from os import walkfilenames = next(walk(mypath), (None, None, []))[2]  # [] if no file


I prefer using the glob module, as it does pattern matching and expansion.

import globprint(glob.glob("/home/adam/*"))

It does pattern matching intuitively

import glob# All files ending with .txtprint(glob.glob("/home/adam/*.txt")) # All files ending with .txt with depth of 2 folderprint(glob.glob("/home/adam/*/*.txt")) 

It will return a list with the queried files:

['/home/adam/file1.txt', '/home/adam/file2.txt', .... ]


os.listdir() - list in the current directory

With listdir in os module you get the files and the folders in the current dir

 import os arr = os.listdir() print(arr)  >>> ['$RECYCLE.BIN', 'work.txt', '3ebooks.txt', 'documents']

Looking in a directory

arr = os.listdir('c:\\files')

glob from glob

with glob you can specify a type of file to list like this

import globtxtfiles = []for file in glob.glob("*.txt"):    txtfiles.append(file)

glob in a list comprehension

mylist = [f for f in glob.glob("*.txt")]

get the full path of only files in the current directory

import osfrom os import listdirfrom os.path import isfile, joincwd = os.getcwd()onlyfiles = [os.path.join(cwd, f) for f in os.listdir(cwd) if os.path.isfile(os.path.join(cwd, f))]print(onlyfiles) ['G:\\getfilesname\\getfilesname.py', 'G:\\getfilesname\\example.txt']

Getting the full path name with os.path.abspath

You get the full path in return

 import os files_path = [os.path.abspath(x) for x in os.listdir()] print(files_path)  ['F:\\documenti\applications.txt', 'F:\\documenti\collections.txt']

Walk: going through sub directories

os.walk returns the root, the directories list and the files list, that is why I unpacked them in r, d, f in the for loop; it, then, looks for other files and directories in the subfolders of the root and so on until there are no subfolders.

import os# Getting the current work directory (cwd)thisdir = os.getcwd()# r=root, d=directories, f = filesfor r, d, f in os.walk(thisdir):    for file in f:        if file.endswith(".docx"):            print(os.path.join(r, file))

os.listdir(): get files in the current directory (Python 2)

In Python 2, if you want the list of the files in the current directory, you have to give the argument as '.' or os.getcwd() in the os.listdir method.

 import os arr = os.listdir('.') print(arr)  >>> ['$RECYCLE.BIN', 'work.txt', '3ebooks.txt', 'documents']

To go up in the directory tree

# Method 1x = os.listdir('..')# Method 2x= os.listdir('/')

Get files: os.listdir() in a particular directory (Python 2 and 3)

 import os arr = os.listdir('F:\\python') print(arr)  >>> ['$RECYCLE.BIN', 'work.txt', '3ebooks.txt', 'documents']

Get files of a particular subdirectory with os.listdir()

import osx = os.listdir("./content")

os.walk('.') - current directory

 import os arr = next(os.walk('.'))[2] print(arr)  >>> ['5bs_Turismo1.pdf', '5bs_Turismo1.pptx', 'esperienza.txt']

next(os.walk('.')) and os.path.join('dir', 'file')

 import os arr = [] for d,r,f in next(os.walk("F:\\_python")):     for file in f:         arr.append(os.path.join(r,file)) for f in arr:     print(files)>>> F:\\_python\\dict_class.py>>> F:\\_python\\programmi.txt

next(os.walk('F:\\') - get the full path - list comprehension

 [os.path.join(r,file) for r,d,f in next(os.walk("F:\\_python")) for file in f]  >>> ['F:\\_python\\dict_class.py', 'F:\\_python\\programmi.txt']

os.walk - get full path - all files in sub dirs**

x = [os.path.join(r,file) for r,d,f in os.walk("F:\\_python") for file in f]print(x)>>> ['F:\\_python\\dict.py', 'F:\\_python\\progr.txt', 'F:\\_python\\readl.py']

os.listdir() - get only txt files

 arr_txt = [x for x in os.listdir() if x.endswith(".txt")] print(arr_txt)  >>> ['work.txt', '3ebooks.txt']

Using glob to get the full path of the files

If I should need the absolute path of the files:

from path import pathfrom glob import globx = [path(f).abspath() for f in glob("F:\\*.txt")]for f in x:    print(f)>>> F:\acquistionline.txt>>> F:\acquisti_2018.txt>>> F:\bootstrap_jquery_ecc.txt

Using os.path.isfile to avoid directories in the list

import os.pathlistOfFiles = [f for f in os.listdir() if os.path.isfile(f)]print(listOfFiles)>>> ['a simple game.py', 'data.txt', 'decorator.py']

Using pathlib from Python 3.4

import pathlibflist = []for p in pathlib.Path('.').iterdir():    if p.is_file():        print(p)        flist.append(p) >>> error.PNG >>> exemaker.bat >>> guiprova.mp3 >>> setup.py >>> speak_gui2.py >>> thumb.PNG

With list comprehension:

flist = [p for p in pathlib.Path('.').iterdir() if p.is_file()]

Alternatively, use pathlib.Path() instead of pathlib.Path(".")

Use glob method in pathlib.Path()

import pathlibpy = pathlib.Path().glob("*.py")for file in py:    print(file)>>> stack_overflow_list.py>>> stack_overflow_list_tkinter.py

Get all and only files with os.walk

import osx = [i[2] for i in os.walk('.')]y=[]for t in x:    for f in t:        y.append(f)print(y)>>> ['append_to_list.py', 'data.txt', 'data1.txt', 'data2.txt', 'data_180617', 'os_walk.py', 'READ2.py', 'read_data.py', 'somma_defaltdic.py', 'substitute_words.py', 'sum_data.py', 'data.txt', 'data1.txt', 'data_180617']

Get only files with next and walk in a directory

 import os x = next(os.walk('F://python'))[2] print(x)  >>> ['calculator.bat','calculator.py']

Get only directories with next and walk in a directory

 import os next(os.walk('F://python'))[1] # for the current dir use ('.')  >>> ['python3','others']

Get all the subdir names with walk

for r,d,f in os.walk("F:\\_python"):    for dirs in d:        print(dirs)>>> .vscode>>> pyexcel>>> pyschool.py>>> subtitles>>> _metaprogramming>>> .ipynb_checkpoints

os.scandir() from Python 3.5 and greater

import osx = [f.name for f in os.scandir() if f.is_file()]print(x)>>> ['calculator.bat','calculator.py']# Another example with scandir (a little variation from docs.python.org)# This one is more efficient than os.listdir.# In this case, it shows the files only in the current directory# where the script is executed.import oswith os.scandir() as i:    for entry in i:        if entry.is_file():            print(entry.name)>>> ebookmaker.py>>> error.PNG>>> exemaker.bat>>> guiprova.mp3>>> setup.py>>> speakgui4.py>>> speak_gui2.py>>> speak_gui3.py>>> thumb.PNG

Examples:

Ex. 1: How many files are there in the subdirectories?

In this example, we look for the number of files that are included in all the directory and its subdirectories.

import osdef count(dir, counter=0):    "returns number of files in dir and subdirs"    for pack in os.walk(dir):        for f in pack[2]:            counter += 1    return dir + " : " + str(counter) + "files"print(count("F:\\python"))>>> 'F:\\\python' : 12057 files'

Ex.2: How to copy all files from a directory to another?

A script to make order in your computer finding all files of a type (default: pptx) and copying them in a new folder.

import osimport shutilfrom path import pathdestination = "F:\\file_copied"# os.makedirs(destination)def copyfile(dir, filetype='pptx', counter=0):    "Searches for pptx (or other - pptx is the default) files and copies them"    for pack in os.walk(dir):        for f in pack[2]:            if f.endswith(filetype):                fullpath = pack[0] + "\\" + f                print(fullpath)                shutil.copy(fullpath, destination)                counter += 1    if counter > 0:        print('-' * 30)        print("\t==> Found in: `" + dir + "` : " + str(counter) + " files\n")for dir in os.listdir():    "searches for folders that starts with `_`"    if dir[0] == '_':        # copyfile(dir, filetype='pdf')        copyfile(dir, filetype='txt')>>> _compiti18\Compito Contabilità 1\conti.txt>>> _compiti18\Compito Contabilità 1\modula4.txt>>> _compiti18\Compito Contabilità 1\moduloa4.txt>>> ------------------------>>> ==> Found in: `_compiti18` : 3 files

Ex. 3: How to get all the files in a txt file

In case you want to create a txt file with all the file names:

import osmylist = ""with open("filelist.txt", "w", encoding="utf-8") as file:    for eachfile in os.listdir():        mylist += eachfile + "\n"    file.write(mylist)

Example: txt with all the files of an hard drive

"""We are going to save a txt file with all the files in your directory.We will use the function walk()"""import os# see all the methods of os# print(*dir(os), sep=", ")listafile = []percorso = []with open("lista_file.txt", "w", encoding='utf-8') as testo:    for root, dirs, files in os.walk("D:\\"):        for file in files:            listafile.append(file)            percorso.append(root + "\\" + file)            testo.write(file + "\n")listafile.sort()print("N. of files", len(listafile))with open("lista_file_ordinata.txt", "w", encoding="utf-8") as testo_ordinato:    for file in listafile:        testo_ordinato.write(file + "\n")with open("percorso.txt", "w", encoding="utf-8") as file_percorso:    for file in percorso:        file_percorso.write(file + "\n")os.system("lista_file.txt")os.system("lista_file_ordinata.txt")os.system("percorso.txt")

All the file of C:\ in one text file

This is a shorter version of the previous code. Change the folder where to start finding the files if you need to start from another position. This code generate a 50 mb on text file on my computer with something less then 500.000 lines with files with the complete path.

import oswith open("file.txt", "w", encoding="utf-8") as filewrite:    for r, d, f in os.walk("C:\\"):        for file in f:            filewrite.write(f"{r + file}\n")

How to write a file with all paths in a folder of a type

With this function you can create a txt file that will have the name of a type of file that you look for (ex. pngfile.txt) with all the full path of all the files of that type. It can be useful sometimes, I think.

import osdef searchfiles(extension='.ttf', folder='H:\\'):    "Create a txt file with all the file of a type"    with open(extension[1:] + "file.txt", "w", encoding="utf-8") as filewrite:        for r, d, f in os.walk(folder):            for file in f:                if file.endswith(extension):                    filewrite.write(f"{r + file}\n")# looking for png file (fonts) in the hard disk H:\searchfiles('.png', 'H:\\')>>> H:\4bs_18\Dolphins5.png>>> H:\4bs_18\Dolphins6.png>>> H:\4bs_18\Dolphins7.png>>> H:\5_18\marketing html\assets\imageslogo2.png>>> H:\7z001.png>>> H:\7z002.png

(New) Find all files and open them with tkinter GUI

I just wanted to add in this 2019 a little app to search for all files in a dir and be able to open them by doubleclicking on the name of the file in the list.enter image description here

import tkinter as tkimport osdef searchfiles(extension='.txt', folder='H:\\'):    "insert all files in the listbox"    for r, d, f in os.walk(folder):        for file in f:            if file.endswith(extension):                lb.insert(0, r + "\\" + file)def open_file():    os.startfile(lb.get(lb.curselection()[0]))root = tk.Tk()root.geometry("400x400")bt = tk.Button(root, text="Search", command=lambda:searchfiles('.png', 'H:\\'))bt.pack()lb = tk.Listbox(root)lb.pack(fill="both", expand=1)lb.bind("<Double-Button>", lambda x: open_file())root.mainloop()


matomo