For a redirect, you have to return a code 301, plus a Location header. Probably you can try something like:

class myHandler(SimpleHTTPServer.SimpleHTTPRequestHandler):   def do_GET(self):       self.send_response(301)       self.send_header('Location','http://www.example.com')       self.end_headers()

Python 3

In python3 it is done very similar to other answers, but different enough to justify demonstration.

This is a script that does nothing but listen on the port passed as argument 1 and send a 302 ("Found" aka Temporary) redirect to the URL passed as argument 2. (And it has a usage message.)

#!/usr/bin/env python3import sysfrom http.server import HTTPServer, BaseHTTPRequestHandlerif len(sys.argv)-1 != 2:    print("""Usage: {} <port_number> <url>    """.format(sys.argv[0]))    sys.exit()class Redirect(BaseHTTPRequestHandler):   def do_GET(self):       self.send_response(302)       self.send_header('Location', sys.argv[2])       self.end_headers()HTTPServer(("", int(sys.argv[1])), Redirect).serve_forever()

You call it like:

sudo ./redirect.py 80 http://jenkins.example.com:8080/

That example ought to give you enough to write what ever kind of function you need.

This is a complete piece of code to redirect, save this file and run it as a python program. to terminate, ctrl + c.

import SimpleHTTPServerimport SocketServerclass myHandler(SimpleHTTPServer.SimpleHTTPRequestHandler):   def do_GET(self):       print self.path       self.send_response(301)       new_path = '%s%s'%('http://newserver.com', self.path)       self.send_header('Location', new_path)       self.end_headers()PORT = 8000handler = SocketServer.TCPServer(("", PORT), myHandler)print "serving at port 8000"handler.serve_forever()