How does the Python conditional operator workaround work?
Python has a construct that is sort of like the ternary operator in C, et al. It works something like this:
my_var = "Retired" if age > 65 else "Working"
and is equivalent to this C code:
my_var = age > 65 ? "Retired" : "Working";
As for how the code you posted works, let's step through it:
("Working","Retired")
creates a 2-tuple (an immutable list) with the element "Working" at index 0, and "Retired" at index 1.
var>65
returns True if var is greater than 65, False if not. When applied to an index, it is converted into 1 (True) or 0 (False). Thus, this boolean value provides an index into the tuple created on the same line.
Why hasn't Python always had a ternary operator? The simple answer is that Guido van Rossum, the author of Python, didn't like/didn't want it, apparently believing that it was an unnecessary construct that could lead to confusing code (and anyone who's seen massively-nested ternary operators in C can probably agree). But for Python 2.5, he relented and added the grammar seen above.
Python (2.5 and above) does indeed have a syntax for what you are looking for:
x = foo if condition else bar
If condition
is True, x
will be set to foo
, otherwise it will be set to bar
.
Examples:
>>> age = 68>>> x = 'Retired' if age > 65 else 'Working'>>> x'Retired'>>> age = 35>>> y = 'Retired' if age > 65 else 'Working'>>> y'Working'
because True casts to 1 and False casts to 0 so if var = 70
("Working","Retired")[var>65]
becomes
("Working", "Retired")[1]
a nice little shortcut ... but I find it can be a little confusing with anything but a simple condition, so I would go with TM's suggestion
"Retired" if var > 65 else "Working"