How to convert a timezone aware string to datetime in Python without dateutil?
As of Python 3.7, datetime.datetime.fromisoformat()
can handle your format:
>>> import datetime>>> datetime.datetime.fromisoformat('2012-11-01T04:16:13-04:00')datetime.datetime(2012, 11, 1, 4, 16, 13, tzinfo=datetime.timezone(datetime.timedelta(days=-1, seconds=72000)))
In older Python versions you can't, not without a whole lot of painstaking manual timezone defining.
Python does not include a timezone database, because it would be outdated too quickly. Instead, Python relies on external libraries, which can have a far faster release cycle, to provide properly configured timezones for you.
As a side-effect, this means that timezone parsing also needs to be an external library. If dateutil
is too heavy-weight for you, use iso8601
instead, it'll parse your specific format just fine:
>>> import iso8601>>> iso8601.parse_date('2012-11-01T04:16:13-04:00')datetime.datetime(2012, 11, 1, 4, 16, 13, tzinfo=<FixedOffset '-04:00'>)
iso8601
is a whopping 4KB small. Compare that tot python-dateutil
's 148KB.
As of Python 3.2 Python can handle simple offset-based timezones, and %z
will parse -hhmm
and +hhmm
timezone offsets in a timestamp. That means that for a ISO 8601 timestamp you'd have to remove the :
in the timezone:
>>> from datetime import datetime>>> iso_ts = '2012-11-01T04:16:13-04:00'>>> datetime.strptime(''.join(iso_ts.rsplit(':', 1)), '%Y-%m-%dT%H:%M:%S%z')datetime.datetime(2012, 11, 1, 4, 16, 13, tzinfo=datetime.timezone(datetime.timedelta(-1, 72000)))
The lack of proper ISO 8601 parsing is being tracked in Python issue 15873.
There are two issues with the code in the original question: there should not be a :
in the timezone and the format string for "timezone as an offset" is lower case %z
not upper %Z
.
This works for me in Python v3.6
>>> from datetime import datetime>>> t = datetime.strptime("2012-11-01T04:16:13-0400", "%Y-%m-%dT%H:%M:%S%z")>>> print(t)2012-11-01 04:16:13-04:00