How to download image using requests
You can either use the
response.raw file object, or iterate over the response.
To use the
response.raw file-like object will not, by default, decode compressed responses (with GZIP or deflate). You can force it to decompress for you anyway by setting the
decode_content attribute to
requests sets it to
False to control decoding itself). You can then use
shutil.copyfileobj() to have Python stream the data to a file object:
import requestsimport shutilr = requests.get(settings.STATICMAP_URL.format(**data), stream=True)if r.status_code == 200: with open(path, 'wb') as f: r.raw.decode_content = True shutil.copyfileobj(r.raw, f)
To iterate over the response use a loop; iterating like this ensures that data is decompressed by this stage:
r = requests.get(settings.STATICMAP_URL.format(**data), stream=True)if r.status_code == 200: with open(path, 'wb') as f: for chunk in r: f.write(chunk)
This'll read the data in 128 byte chunks; if you feel another chunk size works better, use the
Response.iter_content() method with a custom chunk size:
r = requests.get(settings.STATICMAP_URL.format(**data), stream=True)if r.status_code == 200: with open(path, 'wb') as f: for chunk in r.iter_content(1024): f.write(chunk)
Note that you need to open the destination file in binary mode to ensure python doesn't try and translate newlines for you. We also set
stream=True so that
requests doesn't download the whole image into memory first.
Get a file-like object from the request and copy it to a file. This will also avoid reading the whole thing into memory at once.
import shutilimport requestsurl = 'http://example.com/img.png'response = requests.get(url, stream=True)with open('img.png', 'wb') as out_file: shutil.copyfileobj(response.raw, out_file)del response
How about this, a quick solution.
import requestsurl = "http://craphound.com/images/1006884_2adf8fc7.jpg"response = requests.get(url)if response.status_code == 200: with open("/Users/apple/Desktop/sample.jpg", 'wb') as f: f.write(response.content)