How to expand a list to function arguments in Python [duplicate]

python arguments

It exists, but it's hard to search for. I think most people call it the "splat" operator.

It's in the documentation as "Unpacking argument lists".

You'd use it like this: foo(*values). There's also one for dictionaries:

d = {'a': 1, 'b': 2}def foo(a, b):    passfoo(**d)

python arguments

You should use the * operator, like foo(*values) Read the Python doc unpackaging argument lists.

def foo(x,y,z):   return "%d, %d, %d" % (x,y,z)values = [1,2,3]# the solution.foo(*values)

python arguments

Try the following:

foo(*values)

This can be found in the Python docs as Unpacking Argument Lists.

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