How to generate all combination from values in dict of lists in Python

import itertools as itmy_dict={'A':['D','E'],'B':['F','G','H'],'C':['I','J']}allNames = sorted(my_dict)combinations = it.product(*(my_dict[Name] for Name in allNames))print(list(combinations))

Which prints:

[('D', 'F', 'I'), ('D', 'F', 'J'), ('D', 'G', 'I'), ('D', 'G', 'J'), ('D', 'H', 'I'), ('D', 'H', 'J'), ('E', 'F', 'I'), ('E', 'F', 'J'), ('E', 'G', 'I'), ('E', 'G', 'J'), ('E', 'H', 'I'), ('E', 'H', 'J')]

If you want to keep the key:value in the permutations you can use:

import itertoolskeys, values = zip(*my_dict.items())permutations_dicts = [dict(zip(keys, v)) for v in itertools.product(*values)]

this will provide you a list of dicts with the permutations:

print(permutations_dicts)[{'A':'D', 'B':'F', 'C':'I'},  {'A':'D', 'B':'F', 'C':'J'}, ... ]

disclaimer not exactly what the OP was asking, but google send me here looking for that.

How about using ParameterGrid from scikit-learn? It creates a generator over which you can iterate in a normal for loop. In each iteration, you will have a dictionary containing the current parameter combination.

from sklearn.model_selection import ParameterGridparams = {'A':['D','E'],'B':['F','G','H'],'C':['I','J']}param_grid = ParameterGrid(params)for dict_ in param_grid:    # Do something with the current parameter combination in ``dict_``    print(dict_["A"])    print(dict_["B"])    print(dict_["C"])