How to get path of an element in lxml?

Use getpath from ElementTree objects.

from lxml import etree    root = etree.fromstring('''    <foo><bar>Data</bar><bar><baz>data</baz>    <baz>data</baz></bar></foo>    ''')    tree = etree.ElementTree(root)for e in root.iter():    print(tree.getpath(e))

Prints

/foo/foo/bar[1]/foo/bar[2]/foo/bar[2]/baz[1]/foo/bar[2]/baz[2]

See the Xpath and XSLT with lxml from the lxml documentation This gives the path of the element containg the text

An example would be

import cStringIOfrom lxml import etreef = cStringIO.StringIO('<foo><bar><x1>hello</x1><x1>world</x1></bar></foo>')tree = lxml.etree.parse(f)find_text = etree.XPath("//text()")# and print out the required dataprint [tree.getpath( text.getparent()) for text in find_text(tree)]# answer I get is >>> ['/foo/bar/x1[1]', '/foo/bar/x1[2]']

If all you have in your section of code is the element and you want the element's xpath do then element.getroottree().getpath(element) will do the job.

from lxml import etreexml = '''<test>    <a/>    <b>       <i/>       <ii/>    </b></test>'''tree = etree.fromstring(xml)for element in tree.iter():    print element.getroottree().getpath(element)