How to get the current Python interpreter path from inside a Python script? [duplicate]
I found it by:
>>> import sys >>> help(sys)...DATA __stderr__ = <open file '<stderr>', mode 'w' at 0x110029140> __stdin__ = <open file '<stdin>', mode 'r' at 0x110029030> __stdout__ = <open file '<stdout>', mode 'w' at 0x1100290b8> api_version = 1013 argv = [''] builtin_module_names = ('__builtin__', '__main__', '_ast', '_codecs', ... byteorder = 'big' copyright = 'Copyright (c) 2001-2009 Python Software Foundati...ematis... dont_write_bytecode = False exc_value = TypeError('arg is a built-in module',) exec_prefix = '/usr/bin/../../opt/freeware' executable = '/usr/bin/python_64'