How to get the logical right binary shift in python

There isn't a built-in operator for this, but you can easily simulate the >>> yourself:

>>> def rshift(val, n): return val>>n if val >= 0 else (val+0x100000000)>>n... >>> rshift(-1000, 3)536870787>>> rshift(1000, 3)125

The following alternative implementation removes the need for the if:

>>> def rshift(val, n): return (val % 0x100000000) >> n

python bitwise-operators

No, there isn't. The right shift in python is arithmetical.

python bitwise-operators

Numpy provides the right_shift() function that does this:

>>> import numpy>>> numpy.right_shift(1000, 3)125

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