How to import a module given its name as string? How to import a module given its name as string? python python

How to import a module given its name as string?

With Python older than 2.7/3.1, that's pretty much how you do it.

For newer versions, see importlib.import_module for Python 2 and Python 3.

You can use exec if you want to as well.

Or using __import__ you can import a list of modules by doing this:

>>> moduleNames = ['sys', 'os', 're', 'unittest'] >>> moduleNames['sys', 'os', 're', 'unittest']>>> modules = map(__import__, moduleNames)

Ripped straight from Dive Into Python.

The recommended way for Python 2.7 and 3.1 and later is to use importlib module:

importlib.import_module(name, package=None)

Import a module. The name argument specifies what module to import in absolute or relative terms (e.g. either pkg.mod or ..mod). If the name is specified in relative terms, then the package argument must be set to the name of the package which is to act as the anchor for resolving the package name (e.g. import_module('..mod', 'pkg.subpkg') will import pkg.mod).


my_module = importlib.import_module('os.path')

Note: imp is deprecated since Python 3.4 in favor of importlib

As mentioned the imp module provides you loading functions:

imp.load_source(name, path)imp.load_compiled(name, path)

I've used these before to perform something similar.

In my case I defined a specific class with defined methods that were required.Once I loaded the module I would check if the class was in the module, and then create an instance of that class, something like this:

import impimport osdef load_from_file(filepath):    class_inst = None    expected_class = 'MyClass'    mod_name,file_ext = os.path.splitext(os.path.split(filepath)[-1])    if file_ext.lower() == '.py':        py_mod = imp.load_source(mod_name, filepath)    elif file_ext.lower() == '.pyc':        py_mod = imp.load_compiled(mod_name, filepath)    if hasattr(py_mod, expected_class):        class_inst = getattr(py_mod, expected_class)()    return class_inst