how to initialize time() object in python

You can create the object without any values:

>>> import datetime>>> datetime.time()datetime.time(0, 0)

You, however, imported the class datetime from the module, replacing the module itself:

>>> from datetime import datetime>>> datetime.time<method 'time' of 'datetime.datetime' objects>

and that has a different signature:

>>> datetime.time()Traceback (most recent call last):  File "<stdin>", line 1, in <module>TypeError: descriptor 'time' of 'datetime.datetime' object needs an argument>>> datetime.time(0)Traceback (most recent call last):  File "<stdin>", line 1, in <module>TypeError: descriptor 'time' requires a 'datetime.datetime' object but received a 'int'

Either import the whole module, or import the contained classes, but don't mix and match. Stick to:

import datetimeimport time

if you need both modules.

The constructor for time is:

class datetime.time(hour[, minute[, second[, microsecond[, tzinfo]]]])

(from http://docs.python.org/library/datetime.html#time-objects)

This works for me:

In [1]: import datetimeIn [2]: t = datetime.time(0, 0, 0)In [3]: print t00:00:00

It's the fact that you're importing a conflicting datetime from datetime. You probably meant time, except you're also importing a conflicting time. So how about:

import datetime as dt

and

t = dt.time(0, 0, 0)