How to open files given as command line arguments in python? [closed]

If you will write the following script:

#!/usr/bin/env pythonimport syswith open(sys.argv[1], 'r') as my_file:    print(my_file.read())

and run it, it will display the content of the file whose name you pass in the first argument like that:

./my_script.py test.txt

(in the above example this file will be test.txt).

CodeHunter