How to parse timezone with colon

Currently, there is no cure for this, and here is and explanation: https://bugs.python.org/issue15873 more precisely, here: https://bugs.python.org/msg169952 .But you can override this issue, this way:

from datetime import datetimed = "2015-04-30T23:59:59+00:00"if ":" == d[-3:-2]:    d = d[:-3]+d[-2:]print(datetime.strptime(d, "%Y-%m-%dT%H:%M:%S%z"))

Adapted from a rejected edit:

Python >= 3.7:

from datetime import datetimed = "2019-12-25T23:59:59+00:00"print(datetime.strptime(d, "%Y-%m-%dT%H:%M:%S%z"))

Changed in version 3.7: When the %z directive is provided to the strptime() method, the UTC offsets can have a colon as a separator between hours, minutes and seconds. For example, '+01:00:00' will be parsed as an offset of one hour. In addition, providing 'Z' is identical to '+00:00'.

https://docs.python.org/3.7/library/datetime.html

Python <= 3.6

There is no built-in way, but the best solution is:

from datetime import datetimed = "2019-12-25T23:59:59+00:00"if ":" == d[-3]:    d = d[:-3]+d[-2:]print(datetime.strptime(d, "%Y-%m-%dT%H:%M:%S%z"))

Explanations:https://bugs.python.org/issue15873https://bugs.python.org/msg169952

Another solution is to use the dateutil library:

from dateutil import parsermystr = '2015-04-30T23:59:59+00:00'x = parser.parse(mystr)# 2015-04-30 23:59:59+00:00