How to parse XML and count instances of a particular node attribute? How to parse XML and count instances of a particular node attribute? python python

How to parse XML and count instances of a particular node attribute?


I suggest ElementTree. There are other compatible implementations of the same API, such as lxml, and cElementTree in the Python standard library itself; but, in this context, what they chiefly add is even more speed -- the ease of programming part depends on the API, which ElementTree defines.

First build an Element instance root from the XML, e.g. with the XML function, or by parsing a file with something like:

import xml.etree.ElementTree as ETroot = ET.parse('thefile.xml').getroot()

Or any of the many other ways shown at ElementTree. Then do something like:

for type_tag in root.findall('bar/type'):    value = type_tag.get('foobar')    print(value)

And similar, usually pretty simple, code patterns.


minidom is the quickest and pretty straight forward.

XML:

<data>    <items>        <item name="item1"></item>        <item name="item2"></item>        <item name="item3"></item>        <item name="item4"></item>    </items></data>

Python:

from xml.dom import minidomxmldoc = minidom.parse('items.xml')itemlist = xmldoc.getElementsByTagName('item')print(len(itemlist))print(itemlist[0].attributes['name'].value)for s in itemlist:    print(s.attributes['name'].value)

Output:

4item1item1item2item3item4


You can use BeautifulSoup:

from bs4 import BeautifulSoupx="""<foo>   <bar>      <type foobar="1"/>      <type foobar="2"/>   </bar></foo>"""y=BeautifulSoup(x)>>> y.foo.bar.type["foobar"]u'1'>>> y.foo.bar.findAll("type")[<type foobar="1"></type>, <type foobar="2"></type>]>>> y.foo.bar.findAll("type")[0]["foobar"]u'1'>>> y.foo.bar.findAll("type")[1]["foobar"]u'2'


matomo