How to print out http-response header in Python

Update: Based on comment of OP, that only the response headers are needed. Even more easy as written in below documentation of Requests module:

We can view the server's response headers using a Python dictionary:

>>> r.headers{    'content-encoding': 'gzip',    'transfer-encoding': 'chunked',    'connection': 'close',    'server': 'nginx/1.0.4',    'x-runtime': '148ms',    'etag': '"e1ca502697e5c9317743dc078f67693f"',    'content-type': 'application/json'}

And especially the documentation notes:

The dictionary is special, though: it's made just for HTTP headers. According to RFC 7230, HTTP Header names are case-insensitive.

So, we can access the headers using any capitalization we want:

and goes on to explain even more cleverness concerning RFC compliance.

The Requests documentation states:

Using Response.iter_content will handle a lot of what you would otherwise have to handle when using Response.raw directly. When streaming a download, the above is the preferred and recommended way to retrieve the content.

It offers as example:

>>> r = requests.get('https://api.github.com/events', stream=True)>>> r.raw<requests.packages.urllib3.response.HTTPResponse object at 0x101194810>>>> r.raw.read(10)'\x1f\x8b\x08\x00\x00\x00\x00\x00\x00\x03'

But also offers advice on how to do it in practice by redirecting to a file etc. and using a different method:

Using Response.iter_content will handle a lot of what you would otherwise have to handle when using Response.raw directly

How about something like this:

import urllib2req = urllib2.Request('http://www.google.com/')res = urllib2.urlopen(req)print res.info()res.close();

If you are looking for something specific in the header:

For Date: print res.info().get('Date')

Here's how you get just the response headers using the requests library like you mentioned (implementation in Python3):

import requestsurl = "https://www.google.com"response = requests.head(url)print(response.headers) # prints the entire header as a dictionaryprint(response.headers["Content-Length"]) # prints a specific section of the dictionary

It's important to use .head() instead of .get() otherwise you will retrieve the whole file/page like the rest of the answers mentioned.

If you wish to retrieve a URL that requires authentication you can replace the above response with this:

response = requests.head(url, auth=requests.auth.HTTPBasicAuth(username, password))