Python 2

Here is a more straightforward way if all you want to do is save it as a file:

import urlliburllib.urlretrieve("http://www.digimouth.com/news/media/2011/09/google-logo.jpg", "local-filename.jpg")

The second argument is the local path where the file should be saved.

Python 3

As SergO suggested the code below should work with Python 3.

import urllib.requesturllib.request.urlretrieve("http://www.digimouth.com/news/media/2011/09/google-logo.jpg", "local-filename.jpg")

import urllibresource = urllib.urlopen("http://www.digimouth.com/news/media/2011/09/google-logo.jpg")output = open("file01.jpg","wb")output.write(resource.read())output.close()

file01.jpg will contain your image.

I wrote a script that does just this, and it is available on my github for your use.

I utilized BeautifulSoup to allow me to parse any website for images. If you will be doing much web scraping (or intend to use my tool) I suggest you sudo pip install BeautifulSoup. Information on BeautifulSoup is available here.

For convenience here is my code:

from bs4 import BeautifulSoupfrom urllib2 import urlopenimport urllib# use this image scraper from the location that #you want to save scraped images todef make_soup(url):    html = urlopen(url).read()    return BeautifulSoup(html)def get_images(url):    soup = make_soup(url)    #this makes a list of bs4 element tags    images = [img for img in soup.findAll('img')]    print (str(len(images)) + "images found.")    print 'Downloading images to current working directory.'    #compile our unicode list of image links    image_links = [each.get('src') for each in images]    for each in image_links:        filename=each.split('/')[-1]        urllib.urlretrieve(each, filename)    return image_links#a standard call looks like this#get_images('http://www.wookmark.com')