How to sort mongodb with pymongo

.sort(), in pymongo, takes key and direction as parameters.

So if you want to sort by, let's say, id then you should .sort("_id", 1)

For multiple fields:

.sort([("field1", pymongo.ASCENDING), ("field2", pymongo.DESCENDING)])

python mongodb pymongo

You can try this:

db.Account.find().sort("UserName")  db.Account.find().sort("UserName",pymongo.ASCENDING)   db.Account.find().sort("UserName",pymongo.DESCENDING)

python mongodb pymongo

This also works:

db.Account.find().sort('UserName', -1)db.Account.find().sort('UserName', 1)

I'm using this in my code, please comment if i'm doing something wrong here, thanks.

CodeHunter