How to urlencode a querystring in Python?
Python 2
What you're looking for is urllib.quote_plus
:
safe_string = urllib.quote_plus('string_of_characters_like_these:$#@=?%^Q^$')#Value: 'string_of_characters_like_these%3A%24%23%40%3D%3F%25%5EQ%5E%24'
Python 3
In Python 3, the urllib
package has been broken into smaller components. You'll use urllib.parse.quote_plus
(note the parse
child module)
import urllib.parsesafe_string = urllib.parse.quote_plus(...)
You need to pass your parameters into urlencode()
as either a mapping (dict), or a sequence of 2-tuples, like:
>>> import urllib>>> f = { 'eventName' : 'myEvent', 'eventDescription' : 'cool event'}>>> urllib.urlencode(f)'eventName=myEvent&eventDescription=cool+event'
Python 3 or above
Use:
>>> urllib.parse.urlencode(f)eventName=myEvent&eventDescription=cool+event
Note that this does not do url encoding in the commonly used sense (look at the output). For that use urllib.parse.quote_plus
.
Try requests instead of urllib and you don't need to bother with urlencode!
import requestsrequests.get('http://youraddress.com', params=evt.fields)
EDIT:
If you need ordered name-value pairs or multiple values for a name then set params like so:
params=[('name1','value11'), ('name1','value12'), ('name2','value21'), ...]
instead of using a dictionary.