Is it possible to use python suds to read a wsdl file from the file system?

try to use url='file:///path/to/file'

# Python 3import urllib, os url = urllib.parse.urljoin('file:', urllib.request.pathname2url(os.path.abspath("service.xml")))

This is a more complete one liner that will:

Based upon:

the comments in the accepted answer and
this https://stackoverflow.com/a/14298190/622276
and thanks to user Sebastian the updated Python 3 implementation since we should avoid writing legacy python at this time.

# Python 2 (Legacy Python)import urlparse, urllib, osurl = urlparse.urljoin('file:', urllib.pathname2url(os.path.abspath("service.xml")))

python soap wsdl suds

Using pathlib:

def wsdl_uri():    import pathlib    return pathlib.Path(os.path.abspath("resources/your_definition.wsdl")).as_uri()

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