# Limiting floats to two decimal points

You are running into the old problem with floating point numbers that not all numbers can be represented exactly. The command line is just showing you the full floating point form from memory.

With floating point representation, your rounded version is the same number. Since computers are binary, they store floating point numbers as an integer and then divide it by a power of two so 13.95 will be represented in a similar fashion to 125650429603636838/(2**53).

Double precision numbers have 53 bits (16 digits) of precision and regular floats have 24 bits (8 digits) of precision. The floating point type in Python uses double precision to store the values.

For example,

`>>> 125650429603636838/(2**53)13.949999999999999>>> 234042163/(2**24)13.949999988079071>>> a = 13.946>>> print(a)13.946>>> print("%.2f" % a)13.95>>> round(a,2)13.949999999999999>>> print("%.2f" % round(a, 2))13.95>>> print("{:.2f}".format(a))13.95>>> print("{:.2f}".format(round(a, 2)))13.95>>> print("{:.15f}".format(round(a, 2)))13.949999999999999`

If you are after only two decimal places (to display a currency value, for example), then you have a couple of better choices:

- Use integers and store values in cents, not dollars and then divide by 100 to convert to dollars.
- Or use a fixed point number like decimal.

There are new format specifications, **String Format Specification Mini-Language**:

You can do the same as:

`"{:.2f}".format(13.949999999999999)`

**Note 1:** the above returns a string. In order to get as float, simply wrap with `float(...)`

:

`float("{:.2f}".format(13.949999999999999))`

**Note 2:** wrapping with `float()`

doesn't change anything:

`>>> x = 13.949999999999999999>>> x13.95>>> g = float("{:.2f}".format(x))>>> g13.95>>> x == gTrue>>> h = round(x, 2)>>> h13.95>>> x == hTrue`

The built-in `round()`

works just fine in Python 2.7 or later.

Example:

`>>> round(14.22222223, 2)14.22`

Check out the documentation.