Link to class method in python docstring

The solution that works for Sphinx is to prefix the reference with ~.

Per the Sphinx documentation on Cross-referencing Syntax,

If you prefix the content with ~, the link text will only be the last component of the target. For example, :py:meth:~Queue.Queue.get will refer to Queue.Queue.get but only display get as the link text.

So the answer is:

class MyClass():    def foo(self):        print 'foo'    def bar(self):        """This method does the same as :func:`~mymodule.MyClass.foo`"""        print 'foo'

This results in an html looking like this : This method does the same as foo(), and foo() is a link.

However, note that this may not display in Spyder as a link.

If you want to manually specify the text of the link you can use:

:func:`my text <mymodule.MyClass.foo>`

For more information, checkout Cross-referencing Python objects.

It seems to me that you just have to add __name__ or __doc__ to your expression to obtain what you want.
I'm still not sure to have correctly understood the aim

class MyClass():    def foo(self):        """I am the docstring of foo"""        print 'foo'    def bar(self):        """This method does the same as <link to foo>"""        print 'foo'printprint MyClass.fooprint MyClass.foo.__name__print MyClass.foo.__doc__printprint MyClass.__dict__['foo']print MyClass.__dict__['foo'].__name__print MyClass.__dict__['foo'].__doc__

result

<unbound method MyClass.foo>fooI am the docstring of foo<function foo at 0x011C27B0>fooI am the docstring of foo