List Directories and get the name of the Directory
This will print all the subdirectories of the current directory:
print [name for name in os.listdir(".") if os.path.isdir(name)]I'm not sure what you're doing with split("-"), but perhaps this code will help you find a solution?
If you want the full pathnames of the directories, use abspath:
print [os.path.abspath(name) for name in os.listdir(".") if os.path.isdir(name)]Note that these pieces of code will only get the immediate subdirectories. If you want sub-sub-directories and so on, you should use walk as others have suggested.
import osfor root, dirs, files in os.walk(top, topdown=False): for name in dirs: print os.path.join(root, name)Walk is a good built-in for what you are doing
I liked the answer of @RichieHindle but I add small fix for it
import osfolder = './my_folder'sub_folders = [name for name in os.listdir(folder) if os.path.isdir(os.path.join(folder, name))]print(sub_folders)otherwise it's not really work