List minimum in Python with None?

None is being returned

>>> print min([None, 1,2])None>>> None < 1True

If you want to return 1 you have to filter the None away:

>>> L = [None, 1, 2]>>> min(x for x in L if x is not None)1

python list max python-2.x minimum

using a generator expression:

>>> min(value for value in [None,1,2] if value is not None)1

eventually, you may use filter:

>>> min(filter(lambda x: x is not None, [None,1,2]))1

python list max python-2.x minimum

Make None infinite for min():

def noneIsInfinite(value):    if value is None:        return float("inf")    else:        return value>>> print min([1,2,None], key=noneIsInfinite)1

Note: this approach works for python 3 as well.

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