multiple key value pairs in dict comprehension
A dictionary comprehension can only ever produce one key-value pair per iteration. The trick then is to produce an extra loop to separate out the pairs:
{k: v for e in wp_users for k, v in zip(('ID', 'post_author'), e)}
This is equivalent to:
result = {}for e in wp_users: for k, v in zip(('ID', 'post_author'), e): result[k] = v
Note that this just repeats the two keys with each of your wp_users
list, so you are continually replacing the same keys with new values! You may as well just take the last entry in that case:
result = dict(zip(('ID', 'post_author'), wp_users[-1]))
You didn’t share what output you expected however.
If the idea was to have a list of dictionaries, each with two keys, then you want a list comprehension of the above expression applied to each wp_users
entry:
result = [dict(zip(('ID', 'post_author'), e)) for e in wp_users]
That produces the same output as your own, second attempt, but now you have a list of dictionaries. You’ll have to use integer indices to get to one of the dictionaries objects or use further loops.
I came across this old question by accident, and I'm not convinced by the accepted answer.
Accepted answer
What is disturbing with the accepted answer? Consider this:
>>> wp_users = [(1, 'Bill'), (2, 'Bob')]>>> {k: v for e in wp_users for k, v in zip(('ID', 'post_author'), e)}{'ID': 2, 'post_author': 'Bob'}
- First iteration over
wp_users
,e = (1, 'Bill')
, the dict is{'ID':1, 'post_author': 'Bill'}
- Second iteration over
wp_users
,e = (2, 'Bob')
, the dict is totally overwritten to{'ID':2, 'post_author': 'Bob'}
On every iteration, all the values of the dictonary are overwritten. You can avoid a loop and jump directly to the last element of wp_users
:
>>> {k: v for e in wp_users for k, v in zip(('ID', 'post_author'), e)}{'ID': 2, 'post_author': 'Bob'}
Or:
>>> dict(zip(('ID', 'post_author'), wp_users[-1])){'ID': 2, 'post_author': 'Bob'}
I think that's not what you want.
What you are trying to achieve remains unclear, but I see two options: you have a list of users (id, post_author)
and you want to create either a list of dictionaries (one dict per user) or a dictionary of tuples (one tuple per field). You can see the first version as a presentation by lines, and the second as a presentation by columns of the same data.
A list of dictionaries
Try this:
>>> [dict(zip(('ID', 'post_author'), user)) for user in wp_users][{'ID': 1, 'post_author': 'Bill'}, {'ID': 2, 'post_author': 'Bob'}]
For each user
, zip
will create tuples ('ID', id)
and ('post_author', author)
and dict
will generate the dictionaries. Now you can access to the fields like that:
>>> ds = [dict(zip(('ID', 'post_author'), user)) for user in wp_users]>>> ds[0]['post_author']'Bill'
A dictionary of tuples
That's more unusual, but you might want one dictionary whose values are tuples:
>>> dict(zip(('ID', 'post_author'), zip(*wp_users))){'ID': (1, 2), 'post_author': ('Bill', 'Bob')}
zip(*wp_users)
simply creates a list of tuples [(id1, id2, ...), (post_author1, post_author2, ...)]
and the rest is similar to the previous version.
>>> d = dict(zip(('ID', 'post_author'), zip(*wp_users)))>>> d['post_author'][0]'Bill'
Bonus
To extract a column from the line view:
>>> [d['ID'] for d in ds][1, 2]
To extract a line from the column view:
>>> {k:vs[1] for k, vs in d.items()}{'ID': 2, 'post_author': 'Bob'}
I think your problem is that the second version is creating a list of dictionaries, not just one dictionary. You are trying to access a list with a string, which raises the error:
>>> obj = [{'data1': 67, 'data2': 78}]>>> obj[0]['data1']67>>> obj['data1']Traceback (most recent call last): File "<stdin>", line 1, in <module>TypeError: list indices must be integers, not str>>>
Instead, just access the second version as `wp_list[0]['post_author'], and it should work fine:
>>> wp_users = ('Bob', 'Joe', 'Sally')>>> wp_list = [{'ID': (e[0]), 'post_author': (e[1])} for e in wp_users]>>> wp_list[0]['post_author']'o'>>> wp_list[1]['post_author']'o'>>> wp_list[2]['post_author']'a'>>>