numpy matrix vector multiplication [duplicate]

Simplest solution

Use numpy.dot or a.dot(b). See the documentation here.

>>> a = np.array([[ 5, 1 ,3],                   [ 1, 1 ,1],                   [ 1, 2 ,1]])>>> b = np.array([1, 2, 3])>>> print a.dot(b)array([16, 6, 8])

This occurs because numpy arrays are not matrices, and the standard operations *, +, -, / work element-wise on arrays.

Note that while you can use numpy.matrix (as of early 2021) where * will be treated like standard matrix multiplication, numpy.matrix is deprecated and may be removed in future releases.. See the note in its documentation (reproduced below):

It is no longer recommended to use this class, even for linear algebra. Instead use regular arrays. The class may be removed in the future.

Thanks @HopeKing.

Other Solutions

Also know there are other options:

• As noted below, if using python3.5+ the @ operator works as you'd expect:

  >>> print(a @ b)array([16, 6, 8])

• If you want overkill, you can use numpy.einsum. The documentation will give you a flavor for how it works, but honestly, I didn't fully understand how to use it until reading this answer and just playing around with it on my own.

  >>> np.einsum('ji,i->j', a, b)array([16, 6, 8])

• As of mid 2016 (numpy 1.10.1), you can try the experimental numpy.matmul, which works like numpy.dot with two major exceptions: no scalar multiplication but it works with stacks of matrices.

  >>> np.matmul(a, b)array([16, 6, 8])

• numpy.inner functions the same way as numpy.dot for matrix-vector multiplication but behaves differently for matrix-matrix and tensor multiplication (see Wikipedia regarding the differences between the inner product and dot product in general or see this SO answer regarding numpy's implementations).

  >>> np.inner(a, b)array([16, 6, 8])# Beware using for matrix-matrix multiplication though!>>> b = a.T>>> np.dot(a, b)array([[35,  9, 10],       [ 9,  3,  4],       [10,  4,  6]])>>> np.inner(a, b) array([[29, 12, 19],       [ 7,  4,  5],       [ 8,  5,  6]])

Rarer options for edge cases

• If you have tensors (arrays of dimension greater than or equal to one), you can use numpy.tensordot with the optional argument axes=1:

  >>> np.tensordot(a, b, axes=1)array([16,  6,  8])

• Don't use numpy.vdot if you have a matrix of complex numbers, as the matrix will be flattened to a 1D array, then it will try to find the complex conjugate dot product between your flattened matrix and vector (which will fail due to a size mismatch n*m vs n).