pandas pivot_table column names
Using clues from @chrisb's answer, this gave me exactly what I was after:
df2.reset_index(inplace=True)which gives:
id Cost1 Cost2 Cost3 Value1 Value2 Value3 1 124 214 1234 12 23 152 1324 0 234 45 0 34and in case of multiple index columns, this post explains it well. just to be complete, here is how:
df2.columns = [' '.join(col).strip() for col in df2.columns.values]
'id' is the index name, which you can set to None to remove.
In [35]: df2.index.name = NoneIn [36]: df2Out[36]: Cost1 Cost2 Cost3 Value1 Value2 Value31 124 214 1234 12 23 152 1324 0 234 45 0 34