Passing a list of kwargs?
Yes. You do it like this:
def method(**kwargs): print kwargskeywords = {'keyword1': 'foo', 'keyword2': 'bar'}method(keyword1='foo', keyword2='bar')method(**keywords)Running this in Python confirms these produce identical results:
{'keyword2': 'bar', 'keyword1': 'foo'}{'keyword2': 'bar', 'keyword1': 'foo'}
As others have pointed out, you can do what you want by passing a dict. There are various ways to construct a dict. One that preserves the keyword=value style you attempted is to use the dict built-in:
keywords = dict(keyword1 = 'foo', keyword2 = 'bar')Note the versatility of dict; all of these produce the same result:
>>> kw1 = dict(keyword1 = 'foo', keyword2 = 'bar')>>> kw2 = dict({'keyword1':'foo', 'keyword2':'bar'})>>> kw3 = dict([['keyword1', 'foo'], ['keyword2', 'bar']])>>> kw4 = dict(zip(('keyword1', 'keyword2'), ('foo', 'bar')))>>> assert kw1 == kw2 == kw3 == kw4>>>
Do you mean a dict? Sure you can:
def method(**kwargs): #do somethingkeywords = {keyword1: 'foo', keyword2: 'bar'}method(**keywords)