Platform-independent file paths?
You can use os.path and its functions, which take care of OS-specific paths:
>>> import os>>> os.path.join('app', 'subdir', 'dir', 'filename.foo')'app/subdir/dir/filename.foo'On Windows, it should print out with backslashes.
import osos.path.join(os.path.curdir, 'file.name')or
import osos.path.join(os.path.dirname(__file__), 'file.name')depending upon whether it's a module (2) or a single script (1), and whether you're invoking it from the same directory (1), or from a different one (2).
Edit
Looking at the "attempt" you have in your question, I'd guess that you'd want (1).
In Python 3.4+ you can use pathlib:
from pathlib import Pathlibdir = Path(__file__).resolve().with_name('modules')How it works: the __file__ attribute contains the pathname of the file from which the module was loaded. You use it to initialize a Path object , make the path absolute using the resolve() method and replace the final path component using the with_name() method.