Print a list in reverse order with range()?
use reversed()
function:
reversed(range(10))
It's much more meaningful.
Update:
If you want it to be a list (as btk pointed out):
list(reversed(range(10)))
Update:
If you want to use only range
to achieve the same result, you can use all its parameters. range(start, stop, step)
For example, to generate a list [5,4,3,2,1,0]
, you can use the following:
range(5, -1, -1)
It may be less intuitive but as the comments mention, this is more efficient and the right usage of range for reversed list.
Use the 'range' built-in function. The signature is range(start, stop, step)
. This produces a sequence that yields numbers, starting with start
, and ending if stop
has been reached, excluding stop
.
>>> range(9,-1,-1) [9, 8, 7, 6, 5, 4, 3, 2, 1, 0]>>> range(-2, 6, 2) [-2, 0, 2, 4]
In Python 3, this produces a non-list range
object, which functions effectively like a read-only list (but uses way less memory, particularly for large ranges).