Print current call stack from a method in Python code Print current call stack from a method in Python code python python

Print current call stack from a method in Python code


Here's an example of getting the stack via the traceback module, and printing it:

import tracebackdef f():    g()def g():    for line in traceback.format_stack():        print(line.strip())f()# Prints:# File "so-stack.py", line 10, in <module>#     f()# File "so-stack.py", line 4, in f#     g()# File "so-stack.py", line 7, in g#     for line in traceback.format_stack():

If you really only want to print the stack to stderr, you can use:

traceback.print_stack()

Or to print to stdout (useful if want to keep redirected output together), use:

traceback.print_stack(file=sys.stdout)

But getting it via traceback.format_stack() lets you do whatever you like with it.


import tracebacktraceback.print_stack()


inspect.stack() returns the current stack rather than the exception traceback:

import inspectprint inspect.stack()

See https://gist.github.com/FredLoney/5454553 for a log_stack utility function.


matomo