# Python - Create list with numbers between 2 values?

Use `range`

. In Python 2.x it returns a list so all you need is:

`>>> range(11, 17)[11, 12, 13, 14, 15, 16]`

In Python 3.x `range`

is a iterator. So, you need to convert it to a list:

`>>> list(range(11, 17))[11, 12, 13, 14, 15, 16]`

**Note**: The second number is exclusive. So, here it needs to be `16+1`

= `17`

EDIT:

To respond to the question about incrementing by `0.5`

, the easiest option would probably be to use numpy's `arange()`

and `.tolist()`

:

`>>> import numpy as np>>> np.arange(11, 17, 0.5).tolist()[11.0, 11.5, 12.0, 12.5, 13.0, 13.5, 14.0, 14.5, 15.0, 15.5, 16.0, 16.5]`

You seem to be looking for `range()`

:

`>>> x1=11>>> x2=16>>> range(x1, x2+1)[11, 12, 13, 14, 15, 16]>>> list1 = range(x1, x2+1)>>> list1[11, 12, 13, 14, 15, 16]`

For incrementing by `0.5`

instead of `1`

, say:

`>>> list2 = [x*0.5 for x in range(2*x1, 2*x2+1)]>>> list2[11.0, 11.5, 12.0, 12.5, 13.0, 13.5, 14.0, 14.5, 15.0, 15.5, 16.0]`