Python - Create list with numbers between 2 values?
Use range
. In Python 2.x it returns a list so all you need is:
>>> range(11, 17)[11, 12, 13, 14, 15, 16]
In Python 3.x range
is a iterator. So, you need to convert it to a list:
>>> list(range(11, 17))[11, 12, 13, 14, 15, 16]
Note: The second number is exclusive. So, here it needs to be 16+1
= 17
EDIT:
To respond to the question about incrementing by 0.5
, the easiest option would probably be to use numpy's arange()
and .tolist()
:
>>> import numpy as np>>> np.arange(11, 17, 0.5).tolist()[11.0, 11.5, 12.0, 12.5, 13.0, 13.5, 14.0, 14.5, 15.0, 15.5, 16.0, 16.5]
You seem to be looking for range()
:
>>> x1=11>>> x2=16>>> range(x1, x2+1)[11, 12, 13, 14, 15, 16]>>> list1 = range(x1, x2+1)>>> list1[11, 12, 13, 14, 15, 16]
For incrementing by 0.5
instead of 1
, say:
>>> list2 = [x*0.5 for x in range(2*x1, 2*x2+1)]>>> list2[11.0, 11.5, 12.0, 12.5, 13.0, 13.5, 14.0, 14.5, 15.0, 15.5, 16.0]