Python function as a function argument?
Can a Python function be an argument of another function?
Yes.
def myfunc(anotherfunc, extraArgs): anotherfunc(*extraArgs)To be more specific ... with various arguments ...
>>> def x(a,b):... print "param 1 %s param 2 %s"%(a,b)...>>> def y(z,t):... z(*t)...>>> y(x,("hello","manuel"))param 1 hello param 2 manuel>>>
Here's another way using *args (and also optionally), **kwargs:
def a(x, y): print x, ydef b(other, function, *args, **kwargs): function(*args, **kwargs) print otherb('world', a, 'hello', 'dude')Output
hello dudeworldNote that function, *args, **kwargs have to be in that order and have to be the last arguments to the function calling the function.
Functions in Python are first-class objects. But your function definition is a bit off.
def myfunc(anotherfunc, extraArgs, extraKwArgs): return anotherfunc(*extraArgs, **extraKwArgs)