Python - how to execute shell commands with pipe, but without 'shell=True'?
Please look here:
>>> import subprocess>>> p1 = subprocess.Popen(["echo", "This_is_a_testing"], stdout=subprocess.PIPE)>>> p2 = subprocess.Popen(["grep", "-c", "test"], stdin=p1.stdout)>>> 1p1.stdout.close()>>> p2.communicate()(None, None)>>>here you get 1 as output after you write p2 = subprocess.Popen(["grep", "-c", "test"], stdin=p1.stdout), Do not ignore this output in the context of your question.
If this is what you want, then pass stdout=subprocess.PIPE as argument to the second Popen:
>>> p1 = subprocess.Popen(["echo", "This_is_a_testing"], stdout=subprocess.PIPE)>>> p2 = subprocess.Popen(["grep", "test"], stdin=p1.stdout, stdout=subprocess.PIPE)>>> p2.communicate()('This_is_a_testing\n', None)>>>
>>> import subprocess>>> mycmd=subprocess.getoutput('df -h | grep home | gawk \'{ print $1 }\' | cut -d\'/\' -f3')>>> mycmd 'sda6'>>>
From the manual:
to get anything other than None in the result tuple, you need to give stdout=PIPE and/or stderr=PIPE
p2 = subprocess.Popen(["grep", "-c", "test"], stdin=p1.stdout, stdout=subprocess.PIPE)