Python mock patch a function called by another function
First example suggests that f1() and f2() defined in the same module. Hence the following should work:
from foo.bar import f2from mock import patchclass MyTest(TestCase): @patch('foo.bar.f1') def test_f2_2(self, some_func): some_func.return_value = (20, False) num, stat = f2() self.assertEqual((num, stat), (40, False))Patch is on the same as import: @patch('foo.bar.f1')
Here is a good answer on the issue:
http://bhfsteve.blogspot.nl/2012/06/patching-tip-using-mocks-in-python-unit.html
Assuming that you're using this mock libary:
def f1(): return 10, Truedef f2(): num, stat = f1() return 2*num, statimport mockprint f2() # Unchanged f1 -> prints (20, True)with mock.patch('__main__.f1') as MockClass: # replace f1 with MockClass MockClass.return_value = (30, True) # Change the return value print f2() # f2 with changed f1 -> prints (60, True)If your code is divided into modules you would probably need to replace __main__.f1 with the path to your module/function.