Python os.system without the output

Avoid os.system() by all means, and use subprocess instead:

with open(os.devnull, 'wb') as devnull:    subprocess.check_call(['/etc/init.d/apache2', 'restart'], stdout=devnull, stderr=subprocess.STDOUT)

This is the subprocess equivalent of the /etc/init.d/apache2 restart &> /dev/null.

There is subprocess.DEVNULL on Python 3.3+:

#!/usr/bin/env python3from subprocess import DEVNULL, STDOUT, check_callcheck_call(['/etc/init.d/apache2', 'restart'], stdout=DEVNULL, stderr=STDOUT)

Depending on your OS (and that's why as Noufal said, you should use subprocess instead) you can try something like

 os.system("/etc/init.d/apache restart > /dev/null")

or (to mute also the error)

os.system("/etc/init.d/apache restart > /dev/null 2>&1")

You should use the subprocess module using which you can control the stdout and stderr in a flexible fashion. os.system is deprecated.

The subprocess module allows you to create an object which represents a running external process. You can read it from it's stdout/stderr, write to it's stdin, send it signals, terminate it etc. The main object in the module is Popen. There are a bunch of other convenience methods like call etc. The docs are very comprehensive and include a section on replacing the older functions (including os.system).