Regex for existence of some words whose order doesn't matter

See this regex:

/^(?=.*Tim)(?=.*stupid).+/

Regex explanation:

• ^ Asserts position at start of string.
• (?=.*Tim) Asserts that "Tim" is present in the string.
• (?=.*stupid) Asserts that "stupid" is present in the string.
• .+Now that our phrases are present, this string is valid. Go ahead and use .+ or - .++ to match the entire string.

To use lookaheads more exclusively, you can add another (?=.*<to_assert>) group. The entire regex can be simplified as /^(?=.*Tim).*stupid/.

See a regex demo!

>>> import re>>> str ="""... Tim is so stupid.... stupid Tim!... Tim foobar barfoo.... Where is Tim?""">>> m = re.findall(r'^(?=.*Tim)(?=.*stupid).+$', str, re.MULTILINE)>>> m['Tim is so stupid.', 'stupid Tim!']>>> m = re.findall(r'^(?=.*Tim).*stupid', str, re.MULTILINE)>>> m['Tim is so stupid.', 'stupid Tim!']

Read more:

• Regex with exclusion chars and another regex

You can use Positive Lookahead to achieve this. The lookahead approach is nice for matching strings that contain both substrings regardless of order.

pattern = re.compile(r'^(?=.*Tim)(?=.*stupid).*$')

Example:

>>> s = '''Hey there stupid, hey there TimHi Tim, this is stupidHi Tim, this is great'''...>>> import re>>> pattern = re.compile(r'^(?=.*Tim)(?=.*stupid).*$', re.M)>>> pattern.findall(s)# ['Hey there stupid, hey there Tim', 'Hi Tim, this is stupid']